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java面试算法题之子序列与最长公共子串

时间:2016-08-15 编辑:简简单单 来源:一聚教程网


LCS (Longest Common Subsquence/String)

子序列
子串
最长子序列

 代码如下 复制代码

public static int getLongestCommonSubsequence(String a, String b){
    int m = a.length();
    int n = b.length();
    int[][] dp = new int[m+1][n+1];

    for(int i=0; i<=m; i++){
        for(int j=0; j<=n; j++){
            if(i==0 || j==0){
                dp[i][j]=0;
            }else if(a.charAt(i-1)==b.charAt(j-1)){
                dp[i][j] = 1 + dp[i-1][j-1];
            }else{
                dp[i][j] = Math.max(dp[i-1][j], dp[i][j-1]);
            }
        }
    }

    return dp[m][n];
}

最长子串

输出最长长度

 代码如下 复制代码

public static int longestSubstr(String first, String second) {
        if (first == null || second == null || first.length() == 0
                || second.length() == 0) {
            return 0;
        }

        int maxLen = 0;
        int fl = first.length();
        int sl = second.length();
        int[][] table = new int[fl + 1][sl + 1];

        for (int i = 1; i <= fl; i++) {
            for (int j = 1; j <= sl; j++) {
                if (first.charAt(i - 1) == second.charAt(j - 1)) {
                    if (i == 1 || j == 1) {
                        table[i][j] = 1;
                    } else {
                        table[i][j] = table[i - 1][j - 1] + 1;
                    }
                    if (table[i][j] > maxLen) {
                        maxLen = table[i][j];
                    }
                }
            }
        }
        return maxLen;
    }

输出最长子串

 代码如下 复制代码

public static String longestSubstring(String str1, String str2) {
        StringBuilder sb = new StringBuilder();
        if (str1 == null || str1.isEmpty() || str2 == null || str2.isEmpty())
            return "";

        // ignore case
        str1 = str1.toLowerCase();
        str2 = str2.toLowerCase();

        // java initializes them already with 0
        int[][] num = new int[str1.length()][str2.length()];
        int maxlen = 0;
        int lastSubsBegin = 0;

        for (int i = 0; i < str1.length(); i++) {
            for (int j = 0; j < str2.length(); j++) {
                if (str1.charAt(i) == str2.charAt(j)) {
                    if ((i == 0) || (j == 0))
                        num[i][j] = 1;
                    else
                        num[i][j] = 1 + num[i - 1][j - 1];

                    if (num[i][j] > maxlen) {
                        maxlen = num[i][j];
                        // generate substring from str1 => i
                        int thisSubsBegin = i - num[i][j] + 1;
                        if (lastSubsBegin == thisSubsBegin) {
                            // if the current LCS is the same as the last time
                            // this block ran
                            sb.append(str1.charAt(i));
                        } else {
                            // this block resets the string builder if a
                            // different LCS is found
                            lastSubsBegin = thisSubsBegin;
                            sb = new StringBuilder();
                            sb.append(str1.substring(lastSubsBegin, i + 1));
                        }
                    }
                }
            }
        }

        return sb.toString();
    }

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