java获取键盘输入的数字,并进行排序的方法

class Date19_02
 {
  public static void main(String[] arg){
   sortOne();
  }
 public static void sortOne(){
   Scanner sc1 = new Scanner(System.in);  
   System.out.print("n请输入第1个整数:");
   int num1 = sc1.nextInt();
   System.out.print("输入的第1个数字：t"+num1+"n");
   
   System.out.print("n请输入第2个整数:");
   Scanner sc2 = new Scanner(System.in);
   int num2 = sc2.nextInt();
   if (num2 != num1){
    System.out.print("输入的第2个数字：t"+num2+"n");
   }else{
    System.out.print("输入的第2个数与第1个重复,请重试n");
    return ;}
   
   System.out.print("n请输入第3个整数(输满3个即止):");
   Scanner sc3 = new Scanner(System.in);
   int num3 = sc3.nextInt();
   if (num3 != num2){
    System.out.print("输入的第3个数字：t"+num3+"n");}
   else{
    System.out.print("输入的第3个数有重复,请重试n");
    return ;}
   
   int smaller=0, bigger=0, max=0; //类变量须在声明时初始化
  if (num1 < num2){smaller = num1; bigger = num2;}
   else if(num1 > num2){bigger = num1; smaller = num2;}
   
   if (num3 > bigger){max = num3;}
   else{max = bigger;}
   
   System.out.print("n升序排列数字：nt");
   System.out.print(smaller+" "+bigger+" "+max);
  }
 }

import java.util.Arrays; //此源文件的所有导入须写在第一个类之前！
class Date19_02
 {
 public static void main(String[] arg){
   sortTwo();
  }
 public static void sortTwo(){
   int[] array1 = new int[3];
   for (int x=0; x大排列：n");
  for (int y=0; y